x^3-12x^2+40x=0

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Solution for x^3-12x^2+40x=0 equation: 


Simplifying
x3 + -12x2 + 40x = 0

Reorder the terms:
40x + -12x2 + x3 = 0

Solving
40x + -12x2 + x3 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), 'x'.
x(40 + -12x + x2) = 0


Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0

Subproblem 2
Set the factor '(40 + -12x + x2)' equal to zero and attempt to solve:

Simplifying
40 + -12x + x2 = 0

Solving
40 + -12x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -12x + -40 + x2 = 0 + -40

Reorder the terms:
40 + -40 + -12x + x2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -12x + x2 = 0 + -40
-12x + x2 = 0 + -40

Combine like terms: 0 + -40 = -40
-12x + x2 = -40

The x term is -12x.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12x + 36 + x2 = -40 + 36

Reorder the terms:
36 + -12x + x2 = -40 + 36

Combine like terms: -40 + 36 = -4
36 + -12x + x2 = -4

Factor a perfect square on the left side:
(x + -6)(x + -6) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
x = {0}

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